! ! ! Fortran kernel for sparse triangular solve in the BAIJ matrix format ! This ONLY works for factorizations in the NATURAL ORDERING, i.e. ! with MatSolve_SeqBAIJ_4_NaturalOrdering() ! #include ! pure subroutine FortranSolveBAIJ4Unroll(n, x, ai, aj, adiag, a, b) use, intrinsic :: ISO_C_binding implicit none(type, external) MatScalar, intent(in) :: a(0:*) PetscScalar, intent(inout) :: x(0:*) PetscScalar, intent(in) :: b(0:*) PetscInt, intent(in) :: n PetscInt, intent(in) :: ai(0:*), aj(0:*), adiag(0:*) PetscInt :: i, j, jstart, jend PetscInt :: idx, ax, jdx PetscScalar :: s(0:3) PETSC_AssertAlignx(16, a(1)) PETSC_AssertAlignx(16, x(1)) PETSC_AssertAlignx(16, b(1)) PETSC_AssertAlignx(16, ai(1)) PETSC_AssertAlignx(16, aj(1)) PETSC_AssertAlignx(16, adiag(1)) ! ! Forward Solve ! x(0:3) = b(0:3) idx = 0 do i = 1, n - 1 jstart = ai(i) jend = adiag(i) - 1 ax = 16*jstart idx = idx + 4 s(0:3) = b(idx + 0:idx + 3) do j = jstart, jend jdx = 4*aj(j) s(0) = s(0) - (a(ax + 0)*x(jdx + 0) + a(ax + 4)*x(jdx + 1) + a(ax + 8)*x(jdx + 2) + a(ax + 12)*x(jdx + 3)) s(1) = s(1) - (a(ax + 1)*x(jdx + 0) + a(ax + 5)*x(jdx + 1) + a(ax + 9)*x(jdx + 2) + a(ax + 13)*x(jdx + 3)) s(2) = s(2) - (a(ax + 2)*x(jdx + 0) + a(ax + 6)*x(jdx + 1) + a(ax + 10)*x(jdx + 2) + a(ax + 14)*x(jdx + 3)) s(3) = s(3) - (a(ax + 3)*x(jdx + 0) + a(ax + 7)*x(jdx + 1) + a(ax + 11)*x(jdx + 2) + a(ax + 15)*x(jdx + 3)) ax = ax + 16 end do x(idx + 0:idx + 3) = s(0:3) end do ! ! Backward solve the upper triangular ! do i = n - 1, 0, -1 jstart = adiag(i) + 1 jend = ai(i + 1) - 1 ax = 16*jstart s(0:3) = x(idx + 0:idx + 3) do j = jstart, jend jdx = 4*aj(j) s(0) = s(0) - (a(ax + 0)*x(jdx + 0) + a(ax + 4)*x(jdx + 1) + a(ax + 8)*x(jdx + 2) + a(ax + 12)*x(jdx + 3)) s(1) = s(1) - (a(ax + 1)*x(jdx + 0) + a(ax + 5)*x(jdx + 1) + a(ax + 9)*x(jdx + 2) + a(ax + 13)*x(jdx + 3)) s(2) = s(2) - (a(ax + 2)*x(jdx + 0) + a(ax + 6)*x(jdx + 1) + a(ax + 10)*x(jdx + 2) + a(ax + 14)*x(jdx + 3)) s(3) = s(3) - (a(ax + 3)*x(jdx + 0) + a(ax + 7)*x(jdx + 1) + a(ax + 11)*x(jdx + 2) + a(ax + 15)*x(jdx + 3)) ax = ax + 16 end do ax = 16*adiag(i) x(idx + 0) = a(ax + 0)*s(0) + a(ax + 4)*s(1) + a(ax + 8)*s(2) + a(ax + 12)*s(3) x(idx + 1) = a(ax + 1)*s(0) + a(ax + 5)*s(1) + a(ax + 9)*s(2) + a(ax + 13)*s(3) x(idx + 2) = a(ax + 2)*s(0) + a(ax + 6)*s(1) + a(ax + 10)*s(2) + a(ax + 14)*s(3) x(idx + 3) = a(ax + 3)*s(0) + a(ax + 7)*s(1) + a(ax + 11)*s(2) + a(ax + 15)*s(3) idx = idx - 4 end do end subroutine FortranSolveBAIJ4Unroll ! version that does not call BLAS 2 operation for each row block ! pure subroutine FortranSolveBAIJ4(n, x, ai, aj, adiag, a, b, w) use, intrinsic :: ISO_C_binding implicit none MatScalar, intent(in) :: a(0:*) PetscScalar, intent(inout) :: x(0:*), w(0:*) PetscScalar, intent(in) :: b(0:*) PetscInt, intent(in) :: n PetscInt, intent(in) :: ai(0:*), aj(0:*), adiag(0:*) PetscInt :: ii, jj, i, j PetscInt :: jstart, jend, idx, ax, jdx, kdx, nn PetscScalar :: s(0:3) PETSC_AssertAlignx(16, a(1)) PETSC_AssertAlignx(16, w(1)) PETSC_AssertAlignx(16, x(1)) PETSC_AssertAlignx(16, b(1)) PETSC_AssertAlignx(16, ai(1)) PETSC_AssertAlignx(16, aj(1)) PETSC_AssertAlignx(16, adiag(1)) ! ! Forward Solve ! x(0:3) = b(0:3) idx = 0 do i = 1, n - 1 ! ! Pack required part of vector into work array ! kdx = 0 jstart = ai(i) jend = adiag(i) - 1 if (jend - jstart >= 500) error stop 'Overflowing vector FortranSolveBAIJ4()' do j = jstart, jend jdx = 4*aj(j) w(kdx:kdx + 3) = x(jdx:jdx + 3) kdx = kdx + 4 end do ax = 16*jstart idx = idx + 4 s(0:3) = b(idx:idx + 3) ! ! s = s - a(ax:)*w ! nn = 4*(jend - jstart + 1) - 1 do ii = 0, 3 do jj = 0, nn s(ii) = s(ii) - a(ax + 4*jj + ii)*w(jj) end do end do x(idx:idx + 3) = s(0:3) end do ! ! Backward solve the upper triangular ! do i = n - 1, 0, -1 jstart = adiag(i) + 1 jend = ai(i + 1) - 1 ax = 16*jstart s(0:3) = x(idx:idx + 3) ! ! Pack each chunk of vector needed ! kdx = 0 if (jend - jstart >= 500) error stop 'Overflowing vector FortranSolveBAIJ4()' do j = jstart, jend jdx = 4*aj(j) w(kdx:kdx + 3) = x(jdx:jdx + 3) kdx = kdx + 4 end do nn = 4*(jend - jstart + 1) - 1 do ii = 0, 3 do jj = 0, nn s(ii) = s(ii) - a(ax + 4*jj + ii)*w(jj) end do end do ax = 16*adiag(i) x(idx) = a(ax + 0)*s(0) + a(ax + 4)*s(1) + a(ax + 8)*s(2) + a(ax + 12)*s(3) x(idx + 1) = a(ax + 1)*s(0) + a(ax + 5)*s(1) + a(ax + 9)*s(2) + a(ax + 13)*s(3) x(idx + 2) = a(ax + 2)*s(0) + a(ax + 6)*s(1) + a(ax + 10)*s(2) + a(ax + 14)*s(3) x(idx + 3) = a(ax + 3)*s(0) + a(ax + 7)*s(1) + a(ax + 11)*s(2) + a(ax + 15)*s(3) idx = idx - 4 end do end subroutine FortranSolveBAIJ4