---- Minimum Surface Area Problem ----- mx:4, my:4 0 TAO, Function value: 0.210376, Residual: 0.403597 1 TAO, Function value: 0.0110611, Residual: 0.019795 2 TAO, Function value: 4.46413e-05, Residual: 8.72658e-05 Tao Object: 1 MPI process type: ssfls TaoLineSearch Object: 1 MPI process type: armijo Armijo linesearch (projected) : alpha=1. beta=0.5 sigma=0.0001 memsize=1 maximum function evaluations=30 tolerances: ftol=0.0001, rtol=1e-05, gtol=0.9 total number of function evaluations=1 total number of gradient evaluations=1 total number of function/gradient evaluations=0 using variable bounds Termination reason: SUCCESS KSP Object: 1 MPI process type: gmres restart=30, using Classical (unmodified) Gram-Schmidt Orthogonalization with no iterative refinement happy breakdown tolerance 1e-30 maximum iterations=10000, initial guess is zero tolerances: relative=1e-05, absolute=1e-25, divergence=10000. left preconditioning using PRECONDITIONED norm type for convergence test PC Object: 1 MPI process type: ilu out-of-place factorization 0 levels of fill tolerance for zero pivot 1.19209e-05 matrix ordering: natural factor fill ratio given 1., needed 1. Factored matrix: Mat Object: 1 MPI process type: seqaij rows=16, cols=16 package used to perform factorization: petsc total: nonzeros=82, allocated nonzeros=82 not using I-node routines linear system matrix, which is also used to construct the preconditioner: Mat Object: 1 MPI process type: seqaij rows=16, cols=16 total: nonzeros=82, allocated nonzeros=112 total number of mallocs used during MatSetValues calls=0 not using I-node routines total KSP iterations: 9 Active Set subset type: subvec convergence tolerances: gatol=1e-06, grtol=0., steptol=0., gttol=0. Residual in Function/Gradient:=8.72658e-05 convergence tolerances: catol=1e-05, crtol=1e-05 Residual in Constraints:=0. convergence tolerances: function minimum=0.0001 Objective value=4.46413e-05 total number of iterations=2, (max: 2000) total number of constraint function evaluations=5 total number of Jacobian evaluations=3 Solution converged: Minf -- f < fmin