Lines Matching refs:Delta

47 1. & \text{(Approximately) solve} & \mathbf{J}(\mathbf{x}_k) \Delta \mathbf{x}_k &= -\mathbf{F}(\ma…
48 2. & \text{Update} & \mathbf{x}_{k+1} &\gets \mathbf{x}_k + \Delta \mathbf{x}_k.
477 \Delta = \Delta_0 \| F_0 \|_2,
533 % math::L^2 = \|\Delta x\|^2 + \psi^2 (\Delta\lambda)^2,
536 constraint surface, $\Delta\mathbf x$ and $\Delta\lambda$ are the
566 b &= 2\delta\mathbf x^Q\cdot (\Delta\mathbf x + \delta s\delta\mathbf x^F) + 2\psi^2 \Delta\lambda,…
567 c &= \|\Delta\mathbf x + \delta s\delta\mathbf x^F\|^2 + \psi^2 \Delta\lambda^2 - L^2.
571 Since in the first iteration, $\Delta\mathbf x = \delta\mathbf x^F = \mathbf 0$ and
572 $\Delta\lambda = 0$, $b = 0$ and the equation simplifies to a pair of
583 …delta\lambda) = \text{sign}\big(\delta\mathbf x^Q \cdot (\Delta\mathbf x)_{i-1} + \psi^2(\Delta\la…
586 where $(\Delta\mathbf x)_{i-1}$ and $(\Delta\lambda)_{i-1}$ are the
605 \delta \lambda = -\frac{\Delta \mathbf x \cdot \delta \mathbf x^F}{\Delta\mathbf x \cdot \delta\mat…
984 \mathbf{r}_k^{(i)} =  \mathbf{F}'(\mathbf{x}_k) \Delta \mathbf{x}_k + \mathbf{F}(\mathbf{x}_k)