Lines Matching refs:omega
18 …1/2} = x_i^n + \omega A_{ii}^{-1}( b_i - \sum_{j < i} A_{ij} x_j^{n+1/2} - \sum_{j \ge i} A_{ij} …
22 …^{n+1/2} + \omega A_{ii}^{-1}( b_i - \sum_{j \le i} A_{ij} x_j^{n+1/2} - \sum_{j > i} A_{ij} x_j^…
24 … over-relaxation because generally $ \omega $ is greater than one, though on occasion underrelaxat…
28 x_i^{1/2} = \omega A_{ii}^{-1}( b_i - \sum_{j < i} A_{ij} x_j^{1/2})
32 x_i = (1 - \omega) x_i^{1/2} + \omega A_{ii}^{-1}( b_i - \sum_{j < i} A_{ij} x_j^{1/2} - \sum_{j > …
38 x^{1/2} = \omega (L + D)^{-1} b
41 x = (1 - \omega) x^{1/2} + \omega (U + D)^{-1}(b - L x^{1/2}) = x^{1/2} + \omega (U+D)^{-1}(b - A x…
50 tmp = - (x[i] = omega*t[i]*aidiag[i]);
71 x[i] = (1-omega)*x[i] + omega*sum*aidiag[i];
86 x = \omega (L + D)^{-1}b
90 x_i = \omega D_{ii}^{-1}(b_i - \sum_{j<i} A_{ij} x_j)
93 x_i = (D_{ii}/\omega)^{-1}(b_i - \sum_{j<i} A_{ij} x_j)
97 x = (L + D/\omega)^{-1}b
100 …itioner obtained by apply the two step process $ (L + D/\omega)^{-1} $ and then $ (U + D/\omega)^{…
103 (L + D/\omega)^{-1} A (U + D/\omega)^{-1} y = (L + D/\omega)^{-1} b.
105 Then after this system is solved, $ x = (U + D/\omega)^{-1} y$. If an initial guess that is nonzero…
106 initial guess for $ y$ must be computed via $ y = (U + D/\omega) x$.
108 …(L + D/\omega)^{-1} A (U + D/\omega)^{-1} & = & (L + D/\omega)^{-1} (L + D + U) (U + D/\omega)^{-…
109 & = & (L + D/\omega)^{-1} (L + D/\omega + U + D/\omega + D - 2D/\omega) (U + D/\omega)^{-1} \\
110 & = & (U + D/\omega)^{-1} + (L+D/\omega)^{-1}(I + \frac{\omega - 2}{\omega}D(U + D/\omega)^{-1}).