Searched refs:digit (Results 1 – 3 of 3) sorted by relevance
2274 PetscInt digit; in PetscDTSimplexQuadrature() local2275 for (digit = 1; digit < n; digit++) { in PetscDTSimplexQuadrature()2277 if (part[digit - 1] == part[digit] && perm[digit - 1] > perm[digit]) break; in PetscDTSimplexQuadrature()2279 if (digit < n) continue; in PetscDTSimplexQuadrature()2313 for (PetscInt digit = last_digit_with_extra + 1; digit < n; digit++) { in PetscDTSimplexQuadrature() local2314 counts[digit] = PetscMin(limit, total_to_distribute); in PetscDTSimplexQuadrature()2317 for (PetscInt digit = 0, offset = 0; digit < n; digit++) { in PetscDTSimplexQuadrature() local2318 PetscInt count = counts[digit]; in PetscDTSimplexQuadrature()2319 for (PetscInt c = 0; c < count; c++) part[offset++] = digit; in PetscDTSimplexQuadrature()
289 for digit in string.digits: argStr=re.sub(digit," ",argStr)
1363 are getting nearly one digit in reduction of the residual per iteration