xref: /petsc/src/mat/impls/baij/seq/dgefa3.c (revision 2205254efee3a00a594e5e2a3a70f74dcb40bc03)
1 
2 /*
3      Inverts 3 by 3 matrix using partial pivoting.
4 
5        Used by the sparse factorization routines in
6      src/mat/impls/baij/seq
7 
8 
9        This is a combination of the Linpack routines
10     dgefa() and dgedi() specialized for a size of 3.
11 
12 */
13 #include <petscsys.h>
14 
15 #undef __FUNCT__
16 #define __FUNCT__ "PetscKernel_A_gets_inverse_A_3"
17 PetscErrorCode PetscKernel_A_gets_inverse_A_3(MatScalar *a,PetscReal shift)
18 {
19     PetscInt   i__2,i__3,kp1,j,k,l,ll,i,ipvt[3],kb,k3;
20     PetscInt   k4,j3;
21     MatScalar  *aa,*ax,*ay,work[9],stmp;
22     MatReal    tmp,max;
23 
24 /*     gaussian elimination with partial pivoting */
25 
26     PetscFunctionBegin;
27     shift = .333*shift*(1.e-12 + PetscAbsScalar(a[0]) + PetscAbsScalar(a[4]) + PetscAbsScalar(a[8]));
28     /* Parameter adjustments */
29     a       -= 4;
30 
31     for (k = 1; k <= 2; ++k) {
32         kp1 = k + 1;
33         k3  = 3*k;
34         k4  = k3 + k;
35 /*        find l = pivot index */
36 
37         i__2 = 4 - k;
38         aa = &a[k4];
39         max = PetscAbsScalar(aa[0]);
40         l = 1;
41         for (ll=1; ll<i__2; ll++) {
42           tmp = PetscAbsScalar(aa[ll]);
43           if (tmp > max) { max = tmp; l = ll+1;}
44         }
45         l       += k - 1;
46         ipvt[k-1] = l;
47 
48         if (a[l + k3] == 0.0) {
49           if (shift == 0.0) {
50             SETERRQ1(PETSC_COMM_SELF,PETSC_ERR_MAT_LU_ZRPVT,"Zero pivot, row %D",k-1);
51           } else {
52             /* Shift is applied to single diagonal entry */
53             a[l + k3] = shift;
54           }
55         }
56 /*           interchange if necessary */
57 
58         if (l != k) {
59           stmp      = a[l + k3];
60           a[l + k3] = a[k4];
61           a[k4]     = stmp;
62         }
63 
64 /*           compute multipliers */
65 
66         stmp = -1. / a[k4];
67         i__2 = 3 - k;
68         aa = &a[1 + k4];
69         for (ll=0; ll<i__2; ll++) {
70           aa[ll] *= stmp;
71         }
72 
73 /*           row elimination with column indexing */
74 
75         ax = &a[k4+1];
76         for (j = kp1; j <= 3; ++j) {
77             j3   = 3*j;
78             stmp = a[l + j3];
79             if (l != k) {
80               a[l + j3] = a[k + j3];
81               a[k + j3] = stmp;
82             }
83 
84             i__3 = 3 - k;
85             ay = &a[1+k+j3];
86             for (ll=0; ll<i__3; ll++) {
87               ay[ll] += stmp*ax[ll];
88             }
89         }
90     }
91     ipvt[2] = 3;
92     if (a[12] == 0.0) SETERRQ1(PETSC_COMM_SELF,PETSC_ERR_MAT_LU_ZRPVT,"Zero pivot, row %D",2);
93 
94     /*
95          Now form the inverse
96     */
97 
98    /*     compute inverse(u) */
99 
100     for (k = 1; k <= 3; ++k) {
101         k3    = 3*k;
102         k4    = k3 + k;
103         a[k4] = 1.0 / a[k4];
104         stmp  = -a[k4];
105         i__2  = k - 1;
106         aa    = &a[k3 + 1];
107         for (ll=0; ll<i__2; ll++) aa[ll] *= stmp;
108         kp1 = k + 1;
109         if (3 < kp1) continue;
110         ax = aa;
111         for (j = kp1; j <= 3; ++j) {
112             j3        = 3*j;
113             stmp      = a[k + j3];
114             a[k + j3] = 0.0;
115             ay        = &a[j3 + 1];
116             for (ll=0; ll<k; ll++) {
117               ay[ll] += stmp*ax[ll];
118             }
119         }
120     }
121 
122    /*    form inverse(u)*inverse(l) */
123 
124     for (kb = 1; kb <= 2; ++kb) {
125         k   = 3 - kb;
126         k3  = 3*k;
127         kp1 = k + 1;
128         aa  = a + k3;
129         for (i = kp1; i <= 3; ++i) {
130             work[i-1] = aa[i];
131             aa[i]   = 0.0;
132         }
133         for (j = kp1; j <= 3; ++j) {
134             stmp  = work[j-1];
135             ax    = &a[3*j + 1];
136             ay    = &a[k3 + 1];
137             ay[0] += stmp*ax[0];
138             ay[1] += stmp*ax[1];
139             ay[2] += stmp*ax[2];
140         }
141         l = ipvt[k-1];
142         if (l != k) {
143             ax = &a[k3 + 1];
144             ay = &a[3*l + 1];
145             stmp = ax[0]; ax[0] = ay[0]; ay[0] = stmp;
146             stmp = ax[1]; ax[1] = ay[1]; ay[1] = stmp;
147             stmp = ax[2]; ax[2] = ay[2]; ay[2] = stmp;
148         }
149     }
150     PetscFunctionReturn(0);
151 }
152 
153 
154