xref: /petsc/src/mat/impls/baij/seq/dgefa3.c (revision 2b8d69ca7ea5fe9190df62c1dce3bbd66fce84dd)
1 
2 /*
3      Inverts 3 by 3 matrix using gaussian elimination with partial pivoting.
4 
5        Used by the sparse factorization routines in
6      src/mat/impls/baij/seq
7 
8 
9        This is a combination of the Linpack routines
10     dgefa() and dgedi() specialized for a size of 3.
11 
12 */
13 #include <petscsys.h>
14 
15 #undef __FUNCT__
16 #define __FUNCT__ "PetscKernel_A_gets_inverse_A_3"
17 PETSC_EXTERN PetscErrorCode PetscKernel_A_gets_inverse_A_3(MatScalar *a,PetscReal shift,PetscBool allowzeropivot,PetscBool *zeropivotdetected)
18 {
19   PetscInt  i__2,i__3,kp1,j,k,l,ll,i,ipvt[3],kb,k3;
20   PetscInt  k4,j3;
21   MatScalar *aa,*ax,*ay,work[9],stmp;
22   MatReal   tmp,max;
23 
24   PetscFunctionBegin;
25   if (zeropivotdetected) *zeropivotdetected = PETSC_FALSE;
26   shift = .333*shift*(1.e-12 + PetscAbsScalar(a[0]) + PetscAbsScalar(a[4]) + PetscAbsScalar(a[8]));
27 
28   /* Parameter adjustments */
29   a -= 4;
30 
31   for (k = 1; k <= 2; ++k) {
32     kp1 = k + 1;
33     k3  = 3*k;
34     k4  = k3 + k;
35 
36     /* find l = pivot index */
37     i__2 = 4 - k;
38     aa   = &a[k4];
39     max  = PetscAbsScalar(aa[0]);
40     l    = 1;
41     for (ll=1; ll<i__2; ll++) {
42       tmp = PetscAbsScalar(aa[ll]);
43       if (tmp > max) { max = tmp; l = ll+1;}
44     }
45     l        += k - 1;
46     ipvt[k-1] = l;
47 
48     if (a[l + k3] == 0.0) {
49       if (shift == 0.0) {
50         if (allowzeropivot) {
51           PetscErrorCode ierr;
52           ierr = PetscInfo1(NULL,"Zero pivot, row %D\n",k-1);CHKERRQ(ierr);
53           *zeropivotdetected = PETSC_TRUE;
54         } else SETERRQ1(PETSC_COMM_SELF,PETSC_ERR_MAT_LU_ZRPVT,"Zero pivot, row %D",k-1);
55       } else {
56         /* Shift is applied to single diagonal entry */
57         a[l + k3] = shift;
58       }
59     }
60 
61     /* interchange if necessary */
62     if (l != k) {
63       stmp      = a[l + k3];
64       a[l + k3] = a[k4];
65       a[k4]     = stmp;
66     }
67 
68     /* compute multipliers */
69     stmp = -1. / a[k4];
70     i__2 = 3 - k;
71     aa   = &a[1 + k4];
72     for (ll=0; ll<i__2; ll++) aa[ll] *= stmp;
73 
74     /* row elimination with column indexing */
75     ax = &a[k4+1];
76     for (j = kp1; j <= 3; ++j) {
77       j3   = 3*j;
78       stmp = a[l + j3];
79       if (l != k) {
80         a[l + j3] = a[k + j3];
81         a[k + j3] = stmp;
82       }
83 
84       i__3 = 3 - k;
85       ay   = &a[1+k+j3];
86       for (ll=0; ll<i__3; ll++) ay[ll] += stmp*ax[ll];
87     }
88   }
89   ipvt[2] = 3;
90   if (a[12] == 0.0) {
91     if (allowzeropivot) {
92       PetscErrorCode ierr;
93       ierr = PetscInfo1(NULL,"Zero pivot, row %D\n",2);CHKERRQ(ierr);
94       *zeropivotdetected = PETSC_TRUE;
95     } else SETERRQ1(PETSC_COMM_SELF,PETSC_ERR_MAT_LU_ZRPVT,"Zero pivot, row %D",2);
96   }
97 
98   /* Now form the inverse */
99   /* compute inverse(u) */
100   for (k = 1; k <= 3; ++k) {
101     k3    = 3*k;
102     k4    = k3 + k;
103     a[k4] = 1.0 / a[k4];
104     stmp  = -a[k4];
105     i__2  = k - 1;
106     aa    = &a[k3 + 1];
107     for (ll=0; ll<i__2; ll++) aa[ll] *= stmp;
108     kp1 = k + 1;
109     if (3 < kp1) continue;
110     ax = aa;
111     for (j = kp1; j <= 3; ++j) {
112       j3        = 3*j;
113       stmp      = a[k + j3];
114       a[k + j3] = 0.0;
115       ay        = &a[j3 + 1];
116       for (ll=0; ll<k; ll++) ay[ll] += stmp*ax[ll];
117     }
118   }
119 
120   /* form inverse(u)*inverse(l) */
121   for (kb = 1; kb <= 2; ++kb) {
122     k   = 3 - kb;
123     k3  = 3*k;
124     kp1 = k + 1;
125     aa  = a + k3;
126     for (i = kp1; i <= 3; ++i) {
127       work[i-1] = aa[i];
128       aa[i]     = 0.0;
129     }
130     for (j = kp1; j <= 3; ++j) {
131       stmp   = work[j-1];
132       ax     = &a[3*j + 1];
133       ay     = &a[k3 + 1];
134       ay[0] += stmp*ax[0];
135       ay[1] += stmp*ax[1];
136       ay[2] += stmp*ax[2];
137     }
138     l = ipvt[k-1];
139     if (l != k) {
140       ax   = &a[k3 + 1];
141       ay   = &a[3*l + 1];
142       stmp = ax[0]; ax[0] = ay[0]; ay[0] = stmp;
143       stmp = ax[1]; ax[1] = ay[1]; ay[1] = stmp;
144       stmp = ax[2]; ax[2] = ay[2]; ay[2] = stmp;
145     }
146   }
147   PetscFunctionReturn(0);
148 }
149 
150 
151