xref: /petsc/src/mat/impls/baij/seq/dgefa4.c (revision 93c39befdc2c545b92559b48e3c3f7c5a930faa6)
1 
2 #ifndef lint
3 static char vcid[] = "$Id: dgefa4.c,v 1.1 1997/06/10 03:18:18 bsmith Exp bsmith $";
4 #endif
5 /*
6     Inverts 4 by 4 matrix using partial pivoting.
7 */
8 #include "petsc.h"
9 
10 #undef __FUNC__
11 #define __FUNC__ "Kernel_A_gets_inverse_A_4"
12 int Kernel_A_gets_inverse_A_4(Scalar *a)
13 {
14     int     i__2, i__3, kp1, j, k, l,ll,i,ipvt_l[4],*ipvt = ipvt_l-1,kb,k3;
15     int     k4,j3;
16     Scalar  *aa,*ax,*ay,work_l[16],*work = work_l-1,stmp;
17     double  tmp,max;
18 
19 /*     gaussian elimination with partial pivoting */
20 
21     /* Parameter adjustments */
22     a       -= 5;
23 
24     for (k = 1; k <= 3; ++k) {
25 	kp1 = k + 1;
26         k3  = 4*k;
27         k4  = k3 + k;
28 /*        find l = pivot index */
29 
30 	i__2 = 4 - k;
31         aa = &a[k4];
32         max = PetscAbsScalar(aa[0]);
33         l = 1;
34         for ( ll=1; ll<i__2; ll++ ) {
35           tmp = PetscAbsScalar(aa[ll]);
36           if (tmp > max) { max = tmp; l = ll+1;}
37         }
38         l       += k - 1;
39 	ipvt[k] = l;
40 
41 	if (a[l + k3] == 0.) {
42 	  SETERRQ(k,0,"Zero pivot");
43 	}
44 
45 /*           interchange if necessary */
46 
47 	if (l != k) {
48 	  stmp      = a[l + k3];
49 	  a[l + k3] = a[k4];
50 	  a[k4]     = stmp;
51         }
52 
53 /*           compute multipliers */
54 
55 	stmp = -1. / a[k4];
56 	i__2 = 4 - k;
57         aa = &a[1 + k4];
58         for ( ll=0; ll<i__2; ll++ ) {
59           aa[ll] *= stmp;
60         }
61 
62 /*           row elimination with column indexing */
63 
64 	ax = &a[k4+1];
65         for (j = kp1; j <= 4; ++j) {
66             j3   = 4*j;
67 	    stmp = a[l + j3];
68 	    if (l != k) {
69 	      a[l + j3] = a[k + j3];
70 	      a[k + j3] = stmp;
71             }
72 
73 	    i__3 = 4 - k;
74             ay = &a[1+k+j3];
75             for ( ll=0; ll<i__3; ll++ ) {
76               ay[ll] += stmp*ax[ll];
77             }
78 	}
79     }
80     ipvt[4] = 4;
81     if (a[20] == 0.) {
82 	SETERRQ(3,0,"Zero pivot,final row");
83     }
84 
85     /*
86          Now form the inverse
87     */
88 
89    /*     compute inverse(u) */
90 
91     for (k = 1; k <= 4; ++k) {
92         k3    = 4*k;
93         k4    = k3 + k;
94 	a[k4] = 1.0 / a[k4];
95 	stmp  = -a[k4];
96 	i__2  = k - 1;
97         aa    = &a[k3 + 1];
98         for ( ll=0; ll<i__2; ll++ ) aa[ll] *= stmp;
99 	kp1 = k + 1;
100 	if (4 < kp1) continue;
101         ax = aa;
102         for (j = kp1; j <= 4; ++j) {
103             j3        = 4*j;
104 	    stmp      = a[k + j3];
105 	    a[k + j3] = 0.0;
106             ay        = &a[j3 + 1];
107             for ( ll=0; ll<k; ll++ ) {
108               ay[ll] += stmp*ax[ll];
109             }
110 	}
111     }
112 
113    /*    form inverse(u)*inverse(l) */
114 
115     for (kb = 1; kb <= 3; ++kb) {
116 	k   = 4 - kb;
117         k3  = 4*k;
118 	kp1 = k + 1;
119         aa  = a + k3;
120 	for (i = kp1; i <= 4; ++i) {
121 	    work[i] = aa[i];
122 	    aa[i]   = 0.0;
123 	}
124 	for (j = kp1; j <= 4; ++j) {
125 	    stmp  = work[j];
126             ax    = &a[4*j + 1];
127             ay    = &a[k3 + 1];
128             ay[0] += stmp*ax[0];
129             ay[1] += stmp*ax[1];
130             ay[2] += stmp*ax[2];
131             ay[3] += stmp*ax[3];
132 	}
133 	l = ipvt[k];
134 	if (l != k) {
135             ax = &a[k3 + 1];
136             ay = &a[4*l + 1];
137             stmp = ax[0]; ax[0] = ay[0]; ay[0] = stmp;
138             stmp = ax[1]; ax[1] = ay[1]; ay[1] = stmp;
139             stmp = ax[2]; ax[2] = ay[2]; ay[2] = stmp;
140             stmp = ax[3]; ax[3] = ay[3]; ay[3] = stmp;
141 	}
142     }
143     return 0;
144 }
145 
146