xref: /phasta/phSolver/testIC-DSIM/solver.inp (revision 595995161822a203c8467e0e4a253d7bd7d6df32)
1*59599516SKenneth E. Jansen# PHASTA Version 1.5 Input File
2*59599516SKenneth E. Jansen#
3*59599516SKenneth E. Jansen#  Basic format is
4*59599516SKenneth E. Jansen#
5*59599516SKenneth E. Jansen#    Key Phrase  :  Acceptable Value (integer, double, logical, or phrase
6*59599516SKenneth E. Jansen#                                     list of integers, list of doubles )
7*59599516SKenneth E. Jansen#
8*59599516SKenneth E. Jansen
9*59599516SKenneth E. Jansen# To find the Key Phrases, first look in input.config.  There you will
10*59599516SKenneth E. Jansen# find the default values for everything that is allowed to have a
11*59599516SKenneth E. Jansen# default. Some things are not allowed to default and must be entered
12*59599516SKenneth E. Jansen# in this file.  In most cases, the acceptable inputs also appear in
13*59599516SKenneth E. Jansen# the input.config file. To add acceptable inputs you should only have
14*59599516SKenneth E. Jansen# to modify:
15*59599516SKenneth E. Jansen
16*59599516SKenneth E. Jansen#     input_asci.cc :which matches the string and translates it to the
17*59599516SKenneth E. Jansen#                    parameter change. If it is a new parameter, you must
18*59599516SKenneth E. Jansen#                    modify:
19*59599516SKenneth E. Jansen#
20*59599516SKenneth E. Jansen#                      common.h (to carry new parameter through code)
21*59599516SKenneth E. Jansen#                      common_c.h (to carry the parameter from C to Fortran)
22*59599516SKenneth E. Jansen#
23*59599516SKenneth E. Jansen#
24*59599516SKenneth E. Jansen# In case it is not clear by now, # allows you to comment either from the
25*59599516SKenneth E. Jansen# beginning of the line or to the right as shown below.
26*59599516SKenneth E. Jansen#
27*59599516SKenneth E. Jansen#SOLUTION CONTROL <--- These are for your organizational clarity (not required)
28*59599516SKenneth E. Jansen#{                 <---
29*59599516SKenneth E. Jansen     Equation of State: Incompressible     # sets ipress=-1 matflag(1,n)
30*59599516SKenneth E. Jansen     Number of Timesteps:  20        #replaces nsteps(1) (ntseq wired =1)
31*59599516SKenneth E. Jansen     Time Step Size: 0.1             # Delt(1)
32*59599516SKenneth E. Jansen#     Turbulence Model:  RANS         #  No-Model iturb=0, RANS =-1  LES=1
33*59599516SKenneth E. Jansen#}
34*59599516SKenneth E. Jansen
35*59599516SKenneth E. JansenPrint Error Indicators: True
36*59599516SKenneth E. Jansen#MATERIAL PROPERTIES
37*59599516SKenneth E. Jansen#{
38*59599516SKenneth E. Jansen     Viscosity: 0.01            # fills datmat (2 values REQUIRED if iLset=1)
39*59599516SKenneth E. Jansen     Density: 1.0               # ditto
40*59599516SKenneth E. Jansen#     Scalar Diffusivity: 0.1    # fills scdiff(1:nsclrS)
41*59599516SKenneth E. Jansen#}
42*59599516SKenneth E. Jansen
43*59599516SKenneth E. Jansen
44*59599516SKenneth E. Jansen#LINEAR SOLVER
45*59599516SKenneth E. Jansen#{
46*59599516SKenneth E. Jansen     Number of Solves per Left-hand-side Formation: 2  #nupdat/LHSupd(1)
47*59599516SKenneth E. Jansen#}
48*59599516SKenneth E. Jansen
49*59599516SKenneth E. Jansen#DISCRETIZATION CONTROL
50*59599516SKenneth E. Jansen#{
51*59599516SKenneth E. Jansen     Basis Function Order: 1                 # ipord
52*59599516SKenneth E. Jansen     Quadrature Rule on Interior: 2           #int(1)
53*59599516SKenneth E. Jansen     Quadrature Rule on Boundary: 2           #intb(1)
54*59599516SKenneth E. Jansen     Include Viscous Correction in Stabilization: True    # if p=1 idiff=1
55*59599516SKenneth E. Jansen                                                           # if p=2 idiff=2
56*59599516SKenneth E. Jansen     Lumped Mass Fraction on Left-hand-side: 1.0           # flmpl
57*59599516SKenneth E. Jansen     Lumped Mass Fraction on Right-hand-side: 1.0          # flmpr
58*59599516SKenneth E. Jansen#}
59*59599516SKenneth E. Jansen     Surface ID for Integrated Mass: 2
60*59599516SKenneth E. Jansen     Number of Force Surfaces: 1
61*59599516SKenneth E. Jansen     Surface ID's for Force Calculation: 1
62*59599516SKenneth E. Jansen
63*59599516SKenneth E. JansenTURBULENCE MODELING PARAMETERS
64*59599516SKenneth E. Jansen{  #                                  lines below are only read if ||| is true
65*59599516SKenneth E. Jansen	Dynamic Model Type : Standard   # adds zero to iturb       LES
66*59599516SKenneth E. Jansen        Filter Integration Rule: 1  #ifrule adds ifrule-1 to iturb LES
67*59599516SKenneth E. Jansen#	Turbulence Wall Model Type: None  #itwmod=0                RANSorLES
68*59599516SKenneth E. Jansen#	Turbulence Wall Model Type: Slip Velocity  #itwmod=1       RANSorLES
69*59599516SKenneth E. Jansen	Turbulence Wall Model Type: Effective Viscosity  #itwmod=2 RANSorLES
70*59599516SKenneth E. Jansen	Velocity Averaging Steps : 500. # wtavei= 1/this           RANSorLES
71*59599516SKenneth E. Jansen	Dynamic Model Averaging Steps : 500. # dtavei= 1/this      LES
72*59599516SKenneth E. Jansen#  negative values to the two previous entries make their value ISTEP in code
73*59599516SKenneth E. Jansen#  Anil...leave as any negative value
74*59599516SKenneth E. Jansen	Filter Width Ratio        : 3.  # fwr1                     LES
75*59599516SKenneth E. Jansen 	}
76*59599516SKenneth E. Jansen#
77*59599516SKenneth E. Jansen#
78*59599516SKenneth E. Jansen#This last one is brand new.  It allows you to construct your step
79*59599516SKenneth E. Jansen#from elementary operations.  It works under the premise that a step is
80*59599516SKenneth E. Jansen#constructed from from a series of solves and updates.  The table goes like
81*59599516SKenneth E. Jansen#this:
82*59599516SKenneth E. Jansen#     solve flow =  0;             update flow =  1
83*59599516SKenneth E. Jansen# solve scalar 1 = 10;         update scalar 1 = 11
84*59599516SKenneth E. Jansen# solve scalar 2 = 20;         update scalar 2 = 21
85*59599516SKenneth E. Jansen# solve scalar 3 = 30;         update scalar 3 = 31
86*59599516SKenneth E. Jansen#              :                             :
87*59599516SKenneth E. Jansen# solve scalar n = n*10;       update scalar n = n*10+1
88*59599516SKenneth E. Jansen# solve heat     = (n+1)*10;          update T = (n+1)*10+1
89*59599516SKenneth E. Jansen#
90*59599516SKenneth E. Jansen
91*59599516SKenneth E. Jansen#  Below we have an example of solving the flow with two iterations
92*59599516SKenneth E. Jansen# (solve, update, solve,update) what would have been achieve before by
93*59599516SKenneth E. Jansen# setting niter=2
94*59599516SKenneth E. Jansen
95*59599516SKenneth E. Jansen#
96*59599516SKenneth E. Jansen#STEP SEQUENCE
97*59599516SKenneth E. Jansen#{
98*59599516SKenneth E. Jansen#      Step Construction  : 0 1 0 1    # this is the standard two iteration
99*59599516SKenneth E. Jansen#     Step Construction  : 0 1 0 1 0 1 0 1 0 1
100*59599516SKenneth E. Jansen      Step Construction  : 0 1       # this is the standard one iteration
101*59599516SKenneth E. Jansen#      Step Construction  : 0 1 10 11
102*59599516SKenneth E. Jansen#      Step Construction  : 0 1 10 11 0 1 10 11 0 1 10 11 20 21 20 21 20 21
103*59599516SKenneth E. Jansen# This one is one Tony might like where the solver would solve the flow with
104*59599516SKenneth E. Jansen# the first scalar (3 times with an update immediately after each solve)
105*59599516SKenneth E. Jansen# followed by 3 successive solves of the second scalar (with an update after
106*59599516SKenneth E. Jansen# each solve)
107*59599516SKenneth E. Jansen#
108*59599516SKenneth E. Jansen
109*59599516SKenneth E. Jansen
110*59599516SKenneth E. Jansen# NOTE: An update consists of adding the delta from the appropriate
111*59599516SKenneth E. Jansen# solve to the appropriate part of the Y vector, followed by
112*59599516SKenneth E. Jansen# reapplication of the boundary conditions. You have to ask for an
113*59599516SKenneth E. Jansen# update. It is not implicit that it will follow each solve.  This is to
114*59599516SKenneth E. Jansen# enable you to solve successive pieces BEFORE updating the solution as
115*59599516SKenneth E. Jansen# is sometimes convenient/necessary. Here is an example of that
116*59599516SKenneth E. Jansen
117*59599516SKenneth E. Jansen#      Step Construction  : 0 1 10 20 11 21 0 1 10 20 11 21
118*59599516SKenneth E. Jansen# here we solve the flow, update the flow, solve scalar 1, solve scalar 2 (BEFORE UPDATING SCALAR 1) then update both scalars,  then repeat the process
119*59599516SKenneth E. Jansen
120*59599516SKenneth E. Jansen
121*59599516SKenneth E. Jansen#}
122*59599516SKenneth E. Jansen     Data Block Format : binary #iotype, options 'binary','ascii'
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